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  • Relative speed = = (45 + 30) km/hr

    = ( 75 * 5/18)  m/sec

    = ( 125/6) m/sec.

    We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

    So, […]

  • Let the speed of each train be x m/sec.

    Then, the relative speed of the two trains = 2x m/sec.

    So, 2x = [(120 + 120)/12]

    => 2x = 20

    => x = 10.

    Therefore, Speed of each train = 10 m/sec = ( 10 * […]

  • Speed of the first train = ( 120/10) m/sec = 12 m/sec.

    Speed of the second train = ( 120/5) m/sec = 8 m/sec.

    Relative speed = (12 + 8) = 20 m/sec.

    Therefore, Required time = [ (120 + 120)/20 ] sec = 12 sec

  • Let the speed of the second train be x km/hr.

    Relative speed = (x + 50) km/hr

    = [ (x + 50) * 5/18 ] m/sec

    = [ (250 + 5x)/18 ] m/sec.

    Distance covered = (108 + 112) = 220 m.

    Therefore, 220/[( 250 + […]

  • Relative speed = (40 – 20) km/hr = ( 20 * 5/18)  m/sec = ( 50/9)  m/sec.

    Therefore, Length of faster train = ( 50/9 * 5) m = (2509) m

    = 27 (7/9) m

  • 2 kmph = ( 2 * 5/18) m/sec = (5/9) m/sec.

    4 kmph = ( 4 * 5/18)  m/sec = (1/9) m/sec.

    Let the length of the train be x meters and its speed by y m/sec.

    Then, [( x/ (y-5/)]= 9 and,

    [( x/(y-10/9) = […]

  • 4.5 km/hr = ( 4.5 * 5/18)  m/sec = (5/4) m/sec = 1.25 m/sec,

    5.4 km/hr = ( 5.4 * 5/18)  m/sec = (3/2) m/sec = 1.5 m/sec.

    Let the speed of the train be x m/sec.

    Then, (x – 1.25) x 8.4 = (x – 1.5) x 8 […]

  • Let the length of the first train be x meters,

    Then, the length of the second train is ( x/2) meters,

    Relative speed = (48 + 42) kmph = ( 90 * 5/18)  m/sec = 25 m/se,

    Therefore, [x + (x/2)]/25 = 12 or […]

  • Suppose they meet x hours after 7 a.m.

    Distance covered by A in x hours = 20x km.

    Distance covered by B in (x – 1) hours = 25(x – 1) km.

    Therefore, 20x + 25(x – 1) = 110

    => 45x = 135

    => x = […]

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