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Relative speed = = (45 + 30) km/hr
= ( 75 * 5/18) m/sec
= ( 125/6) m/sec.
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
Let the speed of each train be x m/sec.
Then, the relative speed of the two trains = 2x m/sec.
So, 2x = [(120 + 120)/12]
=> 2x = 20
=> x = 10.
Therefore, Speed of each train = 10 m/sec = ( 10 * […]
Speed of the first train = ( 120/10) m/sec = 12 m/sec.
Speed of the second train = ( 120/5) m/sec = 8 m/sec.
Relative speed = (12 + 8) = 20 m/sec.
Therefore, Required time = [ (120 + 120)/20 ] sec = 12 sec
Let the speed of the second train be x km/hr.
Relative speed = (x + 50) km/hr
= [ (x + 50) * 5/18 ] m/sec
= [ (250 + 5x)/18 ] m/sec.
Distance covered = (108 + 112) = 220 m.
Therefore, 220/[( 250 + […]
Relative speed = (40 – 20) km/hr = ( 20 * 5/18) m/sec = ( 50/9) m/sec.
Therefore, Length of faster train = ( 50/9 * 5) m = (2509) m
= 27 (7/9) m
2 kmph = ( 2 * 5/18) m/sec = (5/9) m/sec.
4 kmph = ( 4 * 5/18) m/sec = (1/9) m/sec.
Let the length of the train be x meters and its speed by y m/sec.
Then, [( x/ (y-5/)]= 9 and,
[( x/(y-10/9) = […]
4.5 km/hr = ( 4.5 * 5/18) m/sec = (5/4) m/sec = 1.25 m/sec,
5.4 km/hr = ( 5.4 * 5/18) m/sec = (3/2) m/sec = 1.5 m/sec.
Let the speed of the train be x m/sec.
Then, (x – 1.25) x 8.4 = (x – 1.5) x 8 […]
Let the length of the first train be x meters,
Then, the length of the second train is ( x/2) meters,
Relative speed = (48 + 42) kmph = ( 90 * 5/18) m/sec = 25 m/se,
Therefore, [x + (x/2)]/25 = 12 or […]
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x – 1) hours = 25(x – 1) km.
Therefore, 20x + 25(x – 1) = 110
=> 45x = 135
=> x = […]
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