• Perman is a Japanese manga series that is loved by all kids. And 90’s kids were Die-hard fan of Perman.

  • Also called as Nursery web spiders.

  • El Niño is an abnormal weather pattern caused by the warming of the Pacific Ocean near the equator, off the coast of South America.

  • Maybe the goal was to raise the profile of family farming and smallholder farming.

  • 21st June

  • It cannot be replied with a ‘yes’ or a ‘no’ or labelled real or wrong. If you can respond or respond to Google briefly, it doesn’t inspire intensive research or creative output. Essential issues are also tailored […]

  • Relative speed = = (45 + 30) km/hr

    = ( 75 * 5/18)  m/sec

    = ( 125/6) m/sec.

    We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

    So, […]

  • Let the speed of each train be x m/sec.

    Then, the relative speed of the two trains = 2x m/sec.

    So, 2x = [(120 + 120)/12]

    => 2x = 20

    => x = 10.

    Therefore, Speed of each train = 10 m/sec = ( 10 * […]

  • Speed of the first train = ( 120/10) m/sec = 12 m/sec.

    Speed of the second train = ( 120/5) m/sec = 8 m/sec.

    Relative speed = (12 + 8) = 20 m/sec.

    Therefore, Required time = [ (120 + 120)/20 ] sec = 12 sec

  • Let the speed of the second train be x km/hr.

    Relative speed = (x + 50) km/hr

    = [ (x + 50) * 5/18 ] m/sec

    = [ (250 + 5x)/18 ] m/sec.

    Distance covered = (108 + 112) = 220 m.

    Therefore, 220/[( 250 + […]

  • Relative speed = (40 – 20) km/hr = ( 20 * 5/18)  m/sec = ( 50/9)  m/sec.

    Therefore, Length of faster train = ( 50/9 * 5) m = (2509) m

    = 27 (7/9) m

  • 2 kmph = ( 2 * 5/18) m/sec = (5/9) m/sec.

    4 kmph = ( 4 * 5/18)  m/sec = (1/9) m/sec.

    Let the length of the train be x meters and its speed by y m/sec.

    Then, [( x/ (y-5/)]= 9 and,

    [( x/(y-10/9) = […]

  • 4.5 km/hr = ( 4.5 * 5/18)  m/sec = (5/4) m/sec = 1.25 m/sec,

    5.4 km/hr = ( 5.4 * 5/18)  m/sec = (3/2) m/sec = 1.5 m/sec.

    Let the speed of the train be x m/sec.

    Then, (x – 1.25) x 8.4 = (x – 1.5) x 8 […]

  • Let the length of the first train be x meters,

    Then, the length of the second train is ( x/2) meters,

    Relative speed = (48 + 42) kmph = ( 90 * 5/18)  m/sec = 25 m/se,

    Therefore, [x + (x/2)]/25 = 12 or […]

  • Suppose they meet x hours after 7 a.m.

    Distance covered by A in x hours = 20x km.

    Distance covered by B in (x – 1) hours = 25(x – 1) km.

    Therefore, 20x + 25(x – 1) = 110

    => 45x = 135

    => x = […]

  • Let us name the trains as A and B. Then,

    (A’s speed) : (B’s speed) = √b : √a = √16 : √9 = 4 : 3

  • Medical ID is important because, in the case of an emergency, doctors will glance at your phone and identify what illnesses or medical problems you might have and identify how to call without accessing your phone.

  • You have to know what you want to answer when you ask a question. Once you know what kind of information you need and who to ask, you have to ask your questions in a way that gives you the best possible […]

  • Speed = (72 * 5)/18 m/sec = 20 m/sec.

    Time = 26 sec.

    Let the length of the train be x meters.

    Then, (x + 250)/26 = 20

    => x + 250 = 520

    => x = 270.

  • Let the speed of the slower train be x m/sec,

    Then, speed of the faster train = 2x m/sec,

    Relative speed = (x + 2x) m/sec = 3x m/sec.

    Therefore, (100 + 100)/8 = 3x

    => 24x = 200

    => x = 25/3

    So, […]

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