supriya – Question2answers

supriya asked a new question 1 week ago

Perman is a Japanese manga series that is loved by all kids. And 90’s kids were Die-hard fan of Perman.
supriya answered a question 2 weeks, 4 days ago

Also called as Nursery web spiders.
supriya answered a question 2 weeks, 4 days ago

El Niño is an abnormal weather pattern caused by the warming of the Pacific Ocean near the equator, off the coast of South America.
supriya answered a question 2 weeks, 4 days ago

Maybe the goal was to raise the profile of family farming and smallholder farming.
supriya answered a question 2 weeks, 4 days ago

21st June
supriya wrote a new post, Techniques for Writing Basic Questions Which Will Inspire Learners 2 weeks, 4 days ago

It cannot be replied with a ‘yes’ or a ‘no’ or labelled real or wrong. If you can respond or respond to Google briefly, it doesn’t inspire intensive research or creative output. Essential issues are also tailored […]
supriya asked a new question 2 weeks, 6 days ago

Relative speed = = (45 + 30) km/hr

= ( 75 * 5/18) m/sec

= ( 125/6) m/sec.

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, […]
supriya asked a new question 2 weeks, 6 days ago

Let the speed of each train be x m/sec.

Then, the relative speed of the two trains = 2x m/sec.

So, 2x = [(120 + 120)/12]

=> 2x = 20

=> x = 10.

Therefore, Speed of each train = 10 m/sec = ( 10 * […]
supriya asked a new question 2 weeks, 6 days ago

Speed of the first train = ( 120/10) m/sec = 12 m/sec.

Speed of the second train = ( 120/5) m/sec = 8 m/sec.

Relative speed = (12 + 8) = 20 m/sec.

Therefore, Required time = [ (120 + 120)/20 ] sec = 12 sec
supriya asked a new question 2 weeks, 6 days ago

Let the speed of the second train be x km/hr.

Relative speed = (x + 50) km/hr

= [ (x + 50) * 5/18 ] m/sec

= [ (250 + 5x)/18 ] m/sec.

Distance covered = (108 + 112) = 220 m.

Therefore, 220/[( 250 + […]
supriya asked a new question 2 weeks, 6 days ago

Relative speed = (40 – 20) km/hr = ( 20 * 5/18) m/sec = ( 50/9) m/sec.

Therefore, Length of faster train = ( 50/9 * 5) m = (2509) m

= 27 (7/9) m
supriya asked a new question 2 weeks, 6 days ago

2 kmph = ( 2 * 5/18) m/sec = (5/9) m/sec.

4 kmph = ( 4 * 5/18) m/sec = (1/9) m/sec.

Let the length of the train be x meters and its speed by y m/sec.

Then, [( x/ (y-5/)]= 9 and,

[( x/(y-10/9) = […]
supriya asked a new question 2 weeks, 6 days ago

4.5 km/hr = ( 4.5 * 5/18) m/sec = (5/4) m/sec = 1.25 m/sec,

5.4 km/hr = ( 5.4 * 5/18) m/sec = (3/2) m/sec = 1.5 m/sec.

Let the speed of the train be x m/sec.

Then, (x – 1.25) x 8.4 = (x – 1.5) x 8 […]
supriya asked a new question 2 weeks, 6 days ago

Let the length of the first train be x meters,

Then, the length of the second train is ( x/2) meters,

Relative speed = (48 + 42) kmph = ( 90 * 5/18) m/sec = 25 m/se,

Therefore, [x + (x/2)]/25 = 12 or […]
supriya asked a new question 2 weeks, 6 days ago

Suppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x – 1) hours = 25(x – 1) km.

Therefore, 20x + 25(x – 1) = 110

=> 45x = 135

=> x = […]
supriya asked a new question 2 weeks, 6 days ago

Let us name the trains as A and B. Then,

(A’s speed) : (B’s speed) = √b : √a = √16 : √9 = 4 : 3
supriya answered a question 2 weeks, 6 days ago

Medical ID is important because, in the case of an emergency, doctors will glance at your phone and identify what illnesses or medical problems you might have and identify how to call without accessing your phone.
supriya wrote a new post, How to Ask Good Questions? 3 weeks, 5 days ago

You have to know what you want to answer when you ask a question. Once you know what kind of information you need and who to ask, you have to ask your questions in a way that gives you the best possible […]
supriya asked a new question 3 weeks, 6 days ago

Speed = (72 * 5)/18 m/sec = 20 m/sec.

Time = 26 sec.

Let the length of the train be x meters.

Then, (x + 250)/26 = 20

=> x + 250 = 520

=> x = 270.
supriya asked a new question 3 weeks, 6 days ago

Let the speed of the slower train be x m/sec,

Then, speed of the faster train = 2x m/sec,

Relative speed = (x + 2x) m/sec = 3x m/sec.

Therefore, (100 + 100)/8 = 3x

=> 24x = 200

=> x = 25/3

So, […]
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